STR$ and hexadecimal format

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Fernando Perez
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STR$ and hexadecimal format

Post by Fernando Perez »

It seems to me that there is an error in the help regarding str$ in hexadecimal format or perhaps in the function.
The help manual makes it clear that the [toint] parameter is optional, but if I don't use 1, the result is always zero.
Can you try?
wlog str$(255, "%02X") returns zero and wlog str$(255, "%02X", 1) returns the correct value, FF.
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cicciocb
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Re: STR$ and hexadecimal format

Post by cicciocb »

Hi Fernando,
there are no errors.
The documentation states that, for integers arguments, the "last optional" parameter must be 1
image.png
Probably the problem is the interpretation of the word 'optional' (in this case required if you want print integer numbers)
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Re: STR$ and hexadecimal format

Post by Fernando Perez »

I understand, Francesco.
The thing is that in my limited English I had interpreted that if the number to be formatted was already an integer, it was not necessary to use it.
But in the example it is clear.
Thank you.
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Re: STR$ and hexadecimal format

Post by cicciocb »

[Local Link Removed for Guests] wrote: [Local Link Removed for Guests]Tue Dec 05, 2023 10:10 am I understand, Francesco.
The thing is that in my limited English I had interpreted that if the number to be formatted was already an integer, it was not necessary to use it.
But in the example it is clear.
Thank you.
Maybe someone can propose a text without ambiguity that I can replace in the help.
Any proposal is welcomed
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Re: STR$ and hexadecimal format

Post by Fernando Perez »

For hexadecimal and octal formats, its use is mandatory.
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Re: STR$ and hexadecimal format

Post by cicciocb »

In fact all is written in the help but probably is not clear
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Re: STR$ and hexadecimal format

Post by bugs »

Possibly something like:-
The additional ",1" is required for the number types marked integer in the table below.
:?:
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Re: STR$ and hexadecimal format

Post by Electroguard »

Or maybe instead of :
The last optional format ‘toint’, if =1, permits to convert the number in integer format.

Replace with:
when using the format$ option, an optional end ‘toint’ can be used to convert the number to integer format if toint=1.
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